Given a list of numbers, reorder it in zigzag
order.
Let’s say the given list of numbers is numbers
. Zigzag
order of numbers
should follow the following order:
numbers[0] <= numbers[1] >= numbers[2] <= numbers[3]...
.
{
"numbers": [3, 5, 6, 1, 4, 2]
}
Output:
[3, 6, 1, 5, 2, 4]
Explanation: [2, 5, 3, 4, 1, 6]
is also accepted.
{
"numbers": [3, 1, 3, 1, 2, 4]
}
Output:
[1, 3, 1, 3, 2, 4]
Constraints:
/*
Asymptotic complexity in terms of number of elements `n`:
* Time: O(n).
* Auxiliary space: O(1).
* Total space: O(n).
*/
vector<int> zigzag_sort(vector<int> &numbers) {
for (int i = 0; i + 1 < (int)numbers.size(); i++) {
if (i % 2 == 0 && numbers[i] > numbers[i + 1]) {
swap(numbers[i], numbers[i + 1]);
}
else if (i % 2 == 1 && numbers[i] < numbers[i + 1]) {
swap(numbers[i], numbers[i + 1]);
}
}
return numbers;
}
We hope that these solutions to zigzag sort problem have helped you level up your coding skills. You can expect problems like these at top tech companies like Amazon and Google.
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