Find the longest balanced substring in a given string of letters. A string is balanced if every letter in the string appears in both uppercase and lowercase.
{
"s": "GOogleLEns"
}
Output:
"GOogleLE"
{
"s": "aPPle",
}
Output:
""
Constraints:
1 <= size of the input string <= 105
/*
Asymptotic complexity in terms of the length of string `s` ( = `n`):
* Time: O(n).
* Auxiliary space: O(n).
* Total space: O(n).
*/
string longest_balanced_substring(string s) {
if (s.size() < 2) {
return "";
}
vector<bool> is_upper_present(26, false), is_lower_present(26, false);
for (char c: s) {
if (isupper(c)) {
is_upper_present[c - 'A'] = true;
} else {
is_lower_present[c - 'a'] = true;
}
}
// split_indices will store indices of characters that appear only in either uppercase or lowercase,
// and then split the string by these characters.
vector<int> split_indices;
split_indices.push_back(-1);
for (int i = 0; i < s.size(); i++) {
int char_index = toupper(s[i]) - 'A';
if (!is_upper_present[char_index] or !is_lower_present[char_index]) {
split_indices.push_back(i);
}
}
if (split_indices.size() == 1) {
return s;
}
split_indices.push_back(s.size());
string result = "";
for (int i = 0; i < split_indices.size() - 1; i++) {
string substring = s.substr(split_indices[i] + 1, split_indices[i + 1] - split_indices[i] - 1);
string balanced_substring = longest_balanced_substring(substring);
if (balanced_substring.size() > result.size()) {
result = balanced_substring;
}
}
return result;
}
string find_longest_balanced_substring(string &s) {
return longest_balanced_substring(s);
}
We hope that these solutions to the longest balanced substring problem have helped you level up your coding skills. You can expect problems like these at top tech companies like Amazon and Google.
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